Integrand size = 38, antiderivative size = 45 \[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=-\frac {\cos (e+f x) (c-c \sin (e+f x))^{7/2}}{4 c f \sqrt {a+a \sin (e+f x)}} \]
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Time = 0.23 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {2920, 2817} \[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=-\frac {\cos (e+f x) (c-c \sin (e+f x))^{7/2}}{4 c f \sqrt {a \sin (e+f x)+a}} \]
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Rule 2817
Rule 2920
Rubi steps \begin{align*} \text {integral}& = \frac {\int \sqrt {a+a \sin (e+f x)} (c-c \sin (e+f x))^{7/2} \, dx}{a c} \\ & = -\frac {\cos (e+f x) (c-c \sin (e+f x))^{7/2}}{4 c f \sqrt {a+a \sin (e+f x)}} \\ \end{align*}
Time = 1.36 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.82 \[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=-\frac {\left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^3 \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right ) (c-c \sin (e+f x))^{5/2}}{4 f \sqrt {a (1+\sin (e+f x))}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(150\) vs. \(2(39)=78\).
Time = 0.16 (sec) , antiderivative size = 151, normalized size of antiderivative = 3.36
method | result | size |
default | \(\frac {\left (\left (\cos ^{3}\left (f x +e \right )\right ) \sin \left (f x +e \right )+\cos ^{4}\left (f x +e \right )+3 \left (\cos ^{2}\left (f x +e \right )\right ) \sin \left (f x +e \right )-4 \left (\cos ^{3}\left (f x +e \right )\right )-7 \cos \left (f x +e \right ) \sin \left (f x +e \right )-4 \left (\cos ^{2}\left (f x +e \right )\right )-\sin \left (f x +e \right )+8 \cos \left (f x +e \right )-1\right ) \sqrt {-c \left (\sin \left (f x +e \right )-1\right )}\, c^{2} \left (1+\cos \left (f x +e \right )\right )}{4 f \left (-\cos \left (f x +e \right )+\sin \left (f x +e \right )-1\right ) \sqrt {a \left (1+\sin \left (f x +e \right )\right )}}\) | \(151\) |
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Leaf count of result is larger than twice the leaf count of optimal. 98 vs. \(2 (39) = 78\).
Time = 0.29 (sec) , antiderivative size = 98, normalized size of antiderivative = 2.18 \[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=-\frac {{\left (c^{2} \cos \left (f x + e\right )^{4} - 8 \, c^{2} \cos \left (f x + e\right )^{2} + 7 \, c^{2} + 4 \, {\left (c^{2} \cos \left (f x + e\right )^{2} - 2 \, c^{2}\right )} \sin \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right ) + a} \sqrt {-c \sin \left (f x + e\right ) + c}}{4 \, a f \cos \left (f x + e\right )} \]
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Timed out. \[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=\text {Timed out} \]
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\[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=\int { \frac {{\left (-c \sin \left (f x + e\right ) + c\right )}^{\frac {5}{2}} \cos \left (f x + e\right )^{2}}{\sqrt {a \sin \left (f x + e\right ) + a}} \,d x } \]
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none
Time = 0.29 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.18 \[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=\frac {4 \, c^{\frac {5}{2}} \mathrm {sgn}\left (\sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, f x + \frac {1}{2} \, e\right )\right ) \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{8}}{\sqrt {a} f \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, f x + \frac {1}{2} \, e\right )\right )} \]
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Time = 2.19 (sec) , antiderivative size = 96, normalized size of antiderivative = 2.13 \[ \int \frac {\cos ^2(e+f x) (c-c \sin (e+f x))^{5/2}}{\sqrt {a+a \sin (e+f x)}} \, dx=-\frac {c^2\,\sqrt {-c\,\left (\sin \left (e+f\,x\right )-1\right )}\,\left (28\,\cos \left (e+f\,x\right )+27\,\cos \left (3\,e+3\,f\,x\right )-\cos \left (5\,e+5\,f\,x\right )+48\,\sin \left (2\,e+2\,f\,x\right )-8\,\sin \left (4\,e+4\,f\,x\right )\right )}{64\,f\,\sqrt {a\,\left (\sin \left (e+f\,x\right )+1\right )}\,\left (\sin \left (e+f\,x\right )-1\right )} \]
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